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Fix example in `NodePath.get_name()` documentation 

The output of `node_path.get_name(2)` is stated to be `Sprite`,
but the actual output is `Sprite2D`.
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Krazy_J 2023-11-22 14:07:17 -06:00 committed by GitHub
parent 923ef2b46a
commit b359f8e6f5
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1 changed files with 2 additions and 2 deletions
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doc/classes/NodePath.xml
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@ -121,13 +121,13 @@
var node_path = NodePath("Path2D/PathFollow2D/Sprite2D")
print(node_path.get_name(0)) # Path2D
print(node_path.get_name(1)) # PathFollow2D
print(node_path.get_name(2)) # Sprite
print(node_path.get_name(2)) # Sprite2D
[/gdscript]
[csharp]
var nodePath = new NodePath("Path2D/PathFollow2D/Sprite2D");
GD.Print(nodePath.GetName(0)); // Path2D
GD.Print(nodePath.GetName(1)); // PathFollow2D
GD.Print(nodePath.GetName(2)); // Sprite
GD.Print(nodePath.GetName(2)); // Sprite2D
[/csharp]
[/codeblocks]
</description>